Diferenças entre edições de "Coordenadas cartesianas"
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− | Sendo f uma função | + | Sendo f uma função integrável e positiva, a soma de integrais triplos iterados \(\begin{array}{c}\int_0^1\int_z^1\int_0^1\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dxdydz\\+\int_1^2\int_0^1\int_{2-x}^1\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_0^1\int_0^{1-y}\int_0^{-y-z+1}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dxdzdy\\\end{array}\) pode também ser dada, após uma mudança da ordem de integração, por |
A)\(\fbox{$\begin{array}{c}\int_1^2\int_1^2\int_{3-x}^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_1^{3-x}\int_1^{-x-y+4}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_{3-x}^2\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydzdx\\\end{array}$}\) | A)\(\fbox{$\begin{array}{c}\int_1^2\int_1^2\int_{3-x}^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_1^{3-x}\int_1^{-x-y+4}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_{3-x}^2\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydzdx\\\end{array}$}\) |
Revisão das 10h26min de 30 de agosto de 2016
Metadata
- CONTEXTO : Primeiro ciclo universitário
- AREA: Matemática
- DISCIPLINA: Calculo diferencial e integral 2
- ANO: 1
- LINGUA: pt
- AUTOR: Equipa Calculo diferencial e integral 2
- MATERIA PRINCIPAL:
- DESCRICAO:
- DIFICULDADE: easy
- TEMPO MEDIO DE RESOLUCAO: 15 mn
- TEMPO MAXIMO DE RESOLUCAO: 30 mn
- PALAVRAS CHAVE:
Sendo f uma função integrável e positiva, a soma de integrais triplos iterados \(\begin{array}{c}\int_0^1\int_z^1\int_0^1\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dxdydz\\+\int_1^2\int_0^1\int_{2-x}^1\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_0^1\int_0^{1-y}\int_0^{-y-z+1}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dxdzdy\\\end{array}\) pode também ser dada, após uma mudança da ordem de integração, por
A)\(\fbox{$\begin{array}{c}\int_1^2\int_1^2\int_{3-x}^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_1^{3-x}\int_1^{-x-y+4}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_{3-x}^2\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydzdx\\\end{array}$}\)
B)\(\fbox{$\begin{array}{c}\int_1^2\int_{3-x}^2\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydzdx\\+\int_1^2\int_1^{3-z}\int_1^{-y-z+4}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dxdydz\\+\int_1^2\int_{3-z}^2\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydxdz\\\end{array}$}\)
C)\(\fbox{$\begin{array}{c}\int_1^2\int_{3-x}^2\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydzdx\\+\int_1^2\int_1^{3-x}\int_1^{-x-y+4}\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdydx\\+\int_1^2\int_1^y\int_1^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dxdzdy\\\end{array}$}\)
D)\(\fbox{$\begin{array}{c}\int_1^2\int_1^2\int_z^1\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dydzdx\\+\int_1^2\int_1^2\int_{3-x}^2\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdxdy\\+\int_1^2\int_1^2\int_1^y\text{f}\left(\begin{array}{c}x\\y\\z\\\end{array}\right)dzdxdy\\\end{array}$}\)
E)Nenhuma das anteriores
Para obter o zip que contém as instâncias deste exercício clique aqui(CoordCarte)
Se deseja obter o código fonte que gera os exercícios contacte miguel.dziergwa@ist.utl.pt